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The pulley arrangement of fig. are identical. The mass of the rope is negligible. In (a) mass m is lifted up by attaching a mass (2 m) to the other end of the rope. In (b), m is lifted up by pulling the other end of the rope with a constant downward force F =2 mg. In which case, the acceleration of m is more ? |
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Answer» SOLUTION :Case (a): `a=((2m-m)/(2m+m))g` `a=(g)/(3)` Case (B): FBD of MASS m `ma'=T-mg` ma'=2mg-mg `rArr ma'=mg` a'=g So in case (b) ACCELERATION of m is more. |
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