1.

The quality factor of the coil for a series circuit having R = 10Ω, L = 0.1H, C = 10µF.(a) 1(b) 5(c) 10(d) 15This question was posed to me by my college director while I was bunking the class.This key question is from Bandwidth of an RLC Circuit topic in portion Resonance & Magnetically Coupled Circuit of Network Theory

Answer»

Correct ANSWER is (C) 10

Easy EXPLANATION: The RESONANT frequency is given by fr = 1/(2π√LC)=1/(2π√(0.1×10×10^-6))=159.2 Hz. The relation between quality factor, resonant frequency and bandwidth is Q = fr/BW = 2πfrL/R = (6.28×159.2×0.1)/10=10.



Discussion

No Comment Found

Related InterviewSolutions