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The quantum number of four electrons (el to e4) are given below :- `{:(,n,,l,,m,,s,,),(e1,3,,0,,0,,+1//2,,),(e2,4,,0,,1,,1//2,,),(e3,3,,2,,2,,-1//2,,),(e4,3,,1,,-1,,1//2,,):}` The correct order of decreasing energy of these electrons is :A. `e4gte3gte2gte1`B. `e2gte3gte4gte1`C. `e3gte2gte4gte1`D. none |
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Answer» Correct Answer - C `r_(1)=(r_(2))/(n^(2))" "r_(1)=(r )/(4)" "," "r_(3)=r_(1)xxn^(2)` `r_(3)=r//4xx9" "r_(3)=2.25R` |
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