The radial wave function for 1 s electron in H-atom is `R=(2)/a_(0)^(3//2)e^(-r//a_(0))` where `a_(0)`=radius of `1^(st)` orbit of H-atom . The ratio of probablitiy of `1^(st)` electron in hyrogen atom at distance `a_(0)` from nucleus to that at distance `a_(0)/2` from nucleus.A. equalB. `(1)/etime`C. `(4)/etime`D. `(e)/4time`

The radial wave function for 1 s electron in H-atom is `R=(2)/a_(0)^(3

1.	The radial wave function for 1 s electron in H-atom is `R=(2)/a_(0)^(3//2)e^(-r//a_(0))` where `a_(0)`=radius of `1^(st)` orbit of H-atom . The ratio of probablitiy of `1^(st)` electron in hyrogen atom at distance `a_(0)` from nucleus to that at distance `a_(0)/2` from nucleus.A. equalB. `(1)/etime`C. `(4)/etime`D. `(e)/4time`
Answer» Correct Answer - C probability of finding and electron at a particular distance=`4pi_(2) R^(2)` `P_(1)=4pir^(2)R^(2)=4pir^(2)xx(4)/(a_(0)^(3))e^(-2r//a_(0))` `at" "a_(0)" "p_(1)=4pia_(0)^(2)xx(4)/(a_(0)^(3))e^(-2a_(0)//a_(0))` `at" "a_(0//2)" "p_(2)=4pi(a_(0)^(2))/(4)xx(4)/(a_(0)^(3))e^((-2a_(0))/(2a_(0)))` `at" "a_(0//2)" "p_(2)/(p_(2))=(4pia_(0)^(2)xx(4)/(a_(0)^(3))e^((-2a_(0))/(2a_(0))))/(4pia_(0)^(2)/(4)xx(4)/(a_(0)^(3))e^((-2a_(0))/(2a_(0))))` `(p_(1))/(p_(2))=(e^(-))/((1)/(4)e^(-1))=(4)/(e)`

Discussion

No Comment Found

Related InterviewSolutions

The ratio between the neutrons present in nitrogen atom and silicon atoms with number 14 and 28 is :A. `7:3`B. `3:7`C. `1:2`D. `2:1`
Which one of the following sets of ions represents the collection of isoelectronic species?A. `Na^(+),Mg^(2+),Al^(3+),Cl^(-)`B. `Na^(+),Ca^(2+),Sc^(3+),F^(-)`C. `K^(+),Cl^(-),Mg^(2+),Sc^(3+)`D. `K^(+),Ca^(2+),Sc^(3+),Cl^(-)`
If `I_(0)` is the threshold wavelength for photoelectric emission, 1 the wavelength of light falling on the surface of a metal and m is the mass of the electron, then the velocity of ejected electron is given byA. `[(2h)/(m)(lambda - lambda)]^(1//2)`B. `[(2hc)/(m)(lambda_(0)-lambda)]^(1//2)`C. `[(2hc)/(m){(lambda_(0)-lambda)/(lambda lambda_(0))}]^(1//2)`D. `[(2hc)/(m){(1)(lambda_(0))-(1)/(lambda)}]^(1//2)`
If the threshold wavelength `(lambda_(0))` for spection of electron from metal is `350nm `then work function for the photoelectric emission isA. `1.2 xx 10^(-18) J`B. `1.2 xx 10^(-20) J`C. `6 xx 10^(-29) J`D. `6 xx 10^(-12) J`
Which one of the following sets of ions represents a colloection of isoelectronic species ?A. ` K^+ , Cl^- , Ca^(2+) , Sc^(3+)`B. ` K^+ , Cl^- , Ca^(2+) , Sc^(2+), Sc^(3+)`C. `N^(3-), O^(2-) F^- , S^(2-)`D. `Li^+ , Na^+ , Mg^(2+) , ca^(2+)`.
If `lambda_(0)` is the threshold wavelength for photoelectric emission. `lambda` wavelength of light falling on the surface on the surface of metal, and `m` mass of electron. Then de Broglie wavelength of emitted electron is :-A. `[(h(lambdalambda_(0)))/(2mc(lambda_(0)-lambda))]overset(1)(2)`B. `[(h(lambda_(0)-lambda))/(2mclambdalambda_(0))]overset(1)(2)`C. `[(h(lambda-lambda_(0)))/(2mclambdalambda_(0))]overset(1)(2)`D. `[(hlambdalambda_(0))/(2mc)]overset(1)(2)`
If the threshold wavelength `(lambda_(0))` for ejection of electron from metal is `350 nm ` then work function for the photoelectric emission isA. `1.2 xx 10^-18 J`B. `1.2 xx 10^-20 J`C. `6 xx 10^-19 J`D. `6 xx 10^-12 J`
Elements up to atomic number `103` have been synthesized and studied. If a newly discovered element is found to have an atomic number `106`, its electronic configuration will beA. `[Rn]5 f^14 , 6d^4, 7s^2`B. `[Rn]5 f^14 , 6d^1, 7s^2 7p^3`C. `[Rn]5 f^14 , 6d^6, 7s^0`D. `[Rn]5 f^14 , 6d^5, 7s^1`
The kinetic energy of an electron in the second Bohr orbit of a hydrogen atom is [`a_0` is Bohr radius] :A. `(h^(2))/(4 pi^(2) ma_(0)^(2))`B. `(h^(2))/(16 pi^(2) ma_(0)^(2))`C. `(h^(2))/(32 pi^(2) ma_(0)^(2))`D. `(h^(2))/(64 pi^(2) ma_(0)^(2))`
The kinetic energy of an electron in the second Bohr orbit of a hydrogen atom is [`a_0` is Bohr radius] :A. `h^2/(4pi^2 ma_0^2)`B. `h^2/(16pi^2 ma_0^2)`C. `h^2/(32pi^2 ma_0^2)`D. `h^2/(64pi^2 ma_0^2)`

Discussion

No Comment Found

Related InterviewSolutions

Reply to Comment