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The radionuclide `.^(56)Mn` is being produced in a cyclontron at a constant rate `P` by bombarding a manganese target with deutrons. `.^(56)Mn` has a half-life of `2.5 h` and the target contains large numbers of only the stable manganese isotopes `.^(56)Mn`. The reaction that produces `.^(56)Mn` is `.^(56)Mn +d rarr .^(56)Mn +p` After being bombarded for a long time, the activity of `.^(56)Mn` becomes constant, equal to `13.86 xx 10^(10) s^(-1)`. (Use `1 n2=0.693`, Avagardo number `=6 xx 10^(2)`, atomic weight of `.^(56)Mn=56 g mol^(-1)`). At what constant rate P, `.^(56)Mn` nuclei are being produced in the cyclontron during the bombardment?A. `2 xx 10^(11)nuclei s^(-1)`B. `13.86 xx 10^(10)nuclei s^(-1)`C. `9.6 xx 10^(10)nuclei s^(-1)`D. `6.93 xx 10^(10)nuclei s^(-1)` |
Answer» Correct Answer - b In equilibrium, rate of decay = rate of production |
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