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The radius of hydrogen atom in its ground state is `5.3 xx 10^-11 m`. After collision with an electron it is found to have a radius of `21.2 xx 10^-11 m`. The principal quantum number of the final state of the atom is.A. 2B. 3C. 4D. 5 |
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Answer» Correct Answer - A (a) Radius of `H^-` atoms in its ground state, `r_1 = 5.3 xx 10^-11 meters` Radius of Bohr atom in its nth orbit, `r_n = 5.3 xx 10^-11 (n^2)/(z) meters` For `H-"atom"`, `z=1` and `rn = 2.2 xx 10^-11 meters` `n = ((21.2 xx 10^-11)/(5.3 xx 10^-10))^(1//2) = 2`. |
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