InterviewSolution
Saved Bookmarks
| 1. |
The radius of metal sphere at room temperature T is R and the coefficient of linear expansion of the metal is `alpha`. The sphere is heated a little by a temperature T, so that new temperature is `T+DeltaT`. The increase in volume of sphere is approximatelyA. `2piRalphaDeltaT`B. `piR^(2)alphaDeltaT`C. `4piR^(3)alphaDeltaT/3`D. `4piR^(2)alphaDeltaT` |
|
Answer» d) Since, coefficient of volume expansion `gamma=3 xx ` coefficient of linear expansion `rArr` `gamma` = `3alpha` Now, `1/(DeltaT)((DeltaV)/(V)` = `3alpha` `rArr DeltaV` = `3V.alpha. DeltaT` `rArr` `DeltaV= 4/3piR^(3)xx 3alpha xx DeltaT=4piR^(3)alphaDeltaT` |
|