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The radius of the oxygen nucleus `._(8)^(16)O` is `2.8 xx 10^(-15)m`. Find the radius of lead nucleus `._(82)^(205)Pb`. |
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Answer» `R_(0) = 2.8 xx 10^(-15)m, A_(0) = 16, A_(Pb) = 205 R prop A^(1//3)` `(R_(0))/(R_(Pb)) = ((A_(0))/(A_(Pb)))^(1//3) = (2.8 xx 10^(-15))/(R_(Pb)) = ((16)/(205))^(1//3)` `R_(Pb) = 6.55 xx 10^(-15)m`. |
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