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The ratio of atomic numbers of two elements X and Y is 1 : 7. Radius of 5th orbit ofsingle electron species of X is 3.3 `Å`. Write the electronic con figuration of Y and four quantum numbers for the valence electrons

Answer» The atomic number of B is 73 because its electronic configuration is `[Xe]6s^24gamma^(14)5d^3`
`therefore` Atomic number of A is x , that is 73-54=68
So , its electronic configuration is `[Xe]6s^2 5d^1 4f^(11)`


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