1.

The ratio of energy of photon of `lambda = 2000 Å` to that of `lambda = 4000 Å` isA. `.^1//_(4)`B. 4C. `.^1//_(2)`D. 2

Answer» Correct Answer - D
(d) `E = (hc)/(lamda) , lamda_1 = 2000 Å , 12 = 4000 Å ,`
so `(E_1)/(E_2) = (lamda_2)/(lamda_1) = (4000)/(2000) = 2`.


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