1.

The ratio of ionization energy of `H` and `Be^(+3)` is.A. `1 : 1`B. `1 : 3`C. `1 : 9`D. `1 : 16`

Answer» Correct Answer - D
(d) `IE = E_(prop) - E_n`
`IE prop Z_2`
So, `(IE_H)/(IE_(Be^(_3))) = (1)/(16)`
`:. "ratio is" 1 : 16`.


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