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The ratio of magnetic moments of `Fe(III)` and `Co(II)` is `:`A. `sqrt(5):sqrt(7)`B. `sqrt(35):sqrt(15)`C. `7:3`D. `sqrt(24):sqrt(15)` |
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Answer» Correct Answer - 2 `Fe(III)[Ar]3d^(5),` unpaired electron`=5,` magnetic moment `=sqrt(5(5+2))BM` `CO(II)-[Ar]3d^(7),` unpaired electrons `=3,` magnetic moment `=sqrt(3xx(3+2))BM` |
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