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The ratio of the differrence between the first and second Bohr orbit energies to that between second and third Bohr orbit energies isA. `(1)/(2)`B. `(1)/(3)`C. `(27)/(3)`D. `(5)/(27)` |
Answer» `Delta E = - 2.18 xx 10^(-18)((1)/(n_(1)^(2)) - (1)/(n_(2)^(2))) J" atom" ^(-1)` `Delta E_(2 rarr 1) = - 2.18 xx 10^(-18)((1)/(1^(2)) - (1)/(2^(2)))` ` = - 2.18 xx 10^(-18)((3)/(4))` `Delta E _(3 rarr 2)` = - 2.18 xx 10^(-18) ((5)/(36))` `:. (Delta E_(2-1))/(Delta E_(1-2)) = (3)/(4) xx (36)/(5) = (27)/(5) :. (c )` |
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