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The relative decrease in `VP` of an aqueous glucose dilute solution is found to be `0.018`. Hence, the elevation in boiling point is (it is given `1 molal` aqueous urea solution boils at `100.54^@)C` at `1 atm` pressure)A. `0.018^(@)`B. `0.18^(@)`C. `0.54^(@)`D. `0.03^(@)` |
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Answer» Correct Answer - C `chi_(B)=(DeltaP)/P_(A)^(@)=0.018` `DeltaT_(b)=K_(b).m rArr 0.54=K_(b) = xx1=K_(b)=0.54` `m=chi_(B)/(1-chi_(B))xx1000/(Mw_(A))` `m=0.018/0.982xx1000/18=1.0 rArr DeltaT_(b) = K_(b) xx m=0.54^(@)C` |
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