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The relative decreases in the vapour pressure of an aqueous solution containing `2 mol [Cu(NH_(3)_(3)Cl]` in `3 mol H_(2)O` is `0.50`. On reaction with `AgNO_(3)`, this solution will formA. `1 mol AgCl`B. `0.25 mol AgCl`C. `2 mol AgCl`D. `0.40 mol AgCl` |
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Answer» Correct Answer - A `(DeltaP)/P^(@)=0.50 = (n_(1)i)/(n_(1)i + n_(2))` `0.50 =(2i)/(2i + 3)` `i=1.5 = 1 + x` `x=0.5` Hence,2 mol NaCl will exists as `1 "mol" Cl^(ө)` due to `50%` ionization. |
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