1.

The resistace of a resistor is reduced to half of its initial value, In doing so, other parameters of the circuit remains unchanged. The heating effects in the resistors will become

Answer»

TWO times
half
one fourth
four times

Solution :For same cell (i.e., same VOLTAGE) heating EFFECT `H=(V^2 t)/R`. So if RESISTANCE `R.=R/2` then heating effect
`H.=(V^2t)/R.=(V^2t)/((R//2))=(2V^2t)/R=2H`


Discussion

No Comment Found

Related InterviewSolutions