1.

The resistance of a conducting wire is 10 Omega. If a battery of 1.5 V is connected to it, the electric current flowing through it will be ………………….. .

Answer»

0.15 mA
1.5 mA
15 mA
150 mA

Solution :`R = V/I`
`:. I = V/R = 1.5/10 =0.15`
`=150 XX 10^(-3)`
`=150 mA`


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