1.

The resistance of a wire of 0.01 cm radius is 10Omega. If the resistivity of the material of the wire is 50 xx 10^(-8)ohm meter, find the length of the wire.

Answer»

SOLUTION :Given RADIUS `= 0.01 CM = 0.01 xx10^(-2) ` m .
Resistivity `rho=50xx10^(-8) Omega` m.
Resistance R =` 10 Omega`
`R = rho (L)/(A) =rho (l)/(pir^(2))`
`l= (Rpir^(2))/(rho)`
`(10xx3.14xx0.01xx10^(-2)xx0.01xx10^(-2))/(50xx10^(-8))`
`=(314xx10^(-4))/(50xx10^(-8)xx10^(5))`
Length =`(6.28xx10^(-4))/(10^(-3))` =0.628 m .


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