The second ionization potential of Be is `17.98 eV` if the electron in Be is assumed to move in a spherical orbit with a centeral field of effective nuclearcharge `(Z_(6H))` consisting of the nucless and otherelectron by haw many units of charge in the nucless shicided by other electrons? (the energy of electrons in first Bohr of H is `-13.6 eV)` If the extent of shielding by the if electron of Li atom is the same as you have calculated above , find the ionisation potential of Li

The second ionization potential of Be is `17.98 eV` if the electron in

1.	The second ionization potential of Be is `17.98 eV` if the electron in Be is assumed to move in a spherical orbit with a centeral field of effective nuclearcharge `(Z_(6H))` consisting of the nucless and otherelectron by haw many units of charge in the nucless shicided by other electrons? (the energy of electrons in first Bohr of H is `-13.6 eV)` If the extent of shielding by the if electron of Li atom is the same as you have calculated above , find the ionisation potential of Li
Answer» `IE = (13.6Z_(eff)^(2))/(n^(2)) = 17.98` `Z_(eff) = 2.3` Shieiding extent `= Z - Z_(eff) = 4 - 2.3 = 1.7 ` `Z_(eff)` for lithium `= 3 - 1.7 = 1.3 ` `:.IE of lithium = 13.6 xx (1.3)^(2) = 5.746 eV`

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