InterviewSolution
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InterviewSolution
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The second order derivative of `a sin^3 t ` w.r.t, `a cos^3 t` at `t = pi/4` isA. `(4sqrt(2))/(3a)`B. 2C. `(1)/(12a)`D. 0 |
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Answer» Correct Answer - A Let `y=asin^(3)t" and "x=acos^(3)t`. Then, `(dy)/(dt)=3asin^(2)tcost" and "(dx)/(dt)=-3acos^(2)tsint` `implies" "(dy)/(dx)=-tant` `implies" "(d^(2)y)/(dx^(2))=-sec^(2)t(dt)/(dx)=(sec^(2)t)/(3acos^(2)tsint)` `implies" "((d^(2)y)/(dx^(2)))_(t=pi//4)=(4sqrt(2))/(3a)` |
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