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The series combination of the last elements after replacing 1/s and 1/4Ω with 1/(S+4) is?(a) (3s+4)/2s(s-4)(b) (3s-4)/2s(s-4)(c) (3s+4)/2s(s+4)(d) (3s-4)/2s(s+4)The question was posed to me in an interview for job.Enquiry is from Series and Parallel Combination of Elements topic in portion S-Domain Analysis of Network Theory

Answer»

Correct ANSWER is (c) (3s+4)/2s(s+4)

To explain: We got the IMPEDANCE of last two elements in PARALLEL combination as Z1(s) = 1/(s+4) and now the impedance of CAPACITOR is 1/2s. So the series combination of the last elements is Z2(s) = 1/2s+1/(s+4) = (3s+4)/2s(s+4).



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