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The set of value(s) of `a`for which the function`f(x)=(a x^3)/3+(a+2)x^2+(a-1)x+2`possesses a negative point of inflection is`(-oo,-2)uu(0,oo)`(b) `{-4/5}``(-2,0)`(d) empty setA. `(-oo,-2)cup(0,oo)`B. `{-4//5}`C. `(-2,0)`D. empty set |
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Answer» Correct Answer - 1 `f(x) = ax^(2)+2(a+2)x+(a-1)` `f'(x) =2ax+2(a+2)=0` Thus `x=(+2)/(a)` which is the point of inflection Given that we must have `(a+2)/(a) lt or a in (-oo,-2)cup(0,oo)` |
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