1.

The solubility of Ba(OH)2.H2O at 298 K is 5.6 g per 100 g of water. What is the molality of OH- ions in saturated solution?

Answer»

m = Mass of solute (g) x 1000 /Molar mass of solute x Mass of Solvent(g)

m (Ba(OH)2.H2O) = 5.6 x 1000 /189 x 94.4 = 0.314 m 

m ( OH-) = 2 x m (Ba(OH)2.H2O) = 0.314 x 2 = 0.628 m. 



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