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The solution of the system of equations `sinxsiny=(sqrt(3))/4,cosxcosy=(sqrt(3))/4`are`x_1=pi/3+pi/2(2n+k); n , k in I``y_1=pi/6+pi/2(k-2n); n , k in I``x_2=pi/6+pi/2(2n+k); n , k in I``y_2=pi/3+pi/2(k-2n); n , k in I` |
Answer» `sinx*siny=sqrt3/4` `cosx*cosy+sinxsiny=sqrt3/2` `cos(x-y)=sqrt3/2` `x-y=2npipmpi/6` `cosxcosy=sqrt3/4` `cosxcosy-sinxsiny=0` `cos(x+y)=0` `x+y=(2n+1)pi/2` `x+y=npi+pi/2` `2x=2npipmpi/6+npi+pi/2` `x=(2n+1)pi/2+pi/4pmpi/2` `2y=4pi+pi/2-2npipmpi/6` `y=(1-2n)pi+pi/4pmpi/2`. |
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