1.

The specific conducitivity of a 0.5 M aq. Solution of monobasic acid HA at `27^(@)"C"` is 0.006 `"Scm"^(1)`. It’s molar conductivity at infinite dilution is 200 S `"cm"^(2)"mol"^(-1)`. Calculate osmotic pressure (in atm) of 0.5 M HA(aq) solution at `27^(@)"C"`. Given R`=0.08"L""-atm"//"K""-mol"`

Answer» Correct Answer - 12.72
`"A"_("m")^("C")=("K"xx1000)/"C"=(0.006xx1000)/0.500=12" S cm"^(3)"mol"^(-1)`
`"A"_("m")^("0")=200"scm"^(2)"mol"^(-1)`
`alpha=("A"_("m")^("C"))/("A"_("m")^("0"))=0.06`
For HA, `"n"=2`
`"i"=1+("n"-1)alpha`
`=1+(2-1)xx0.6`
`"i"=1.06`
`pi="i"xx"CRT"`
`=1.06xx0.5xx0.082xx300`
`pi=12.72"atm"`


Discussion

No Comment Found

Related InterviewSolutions