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The specific conducitivity of a 0.5 M aq. Solution of monobasic acid HA at `27^(@)"C"` is 0.006 `"Scm"^(1)`. It’s molar conductivity at infinite dilution is 200 S `"cm"^(2)"mol"^(-1)`. Calculate osmotic pressure (in atm) of 0.5 M HA(aq) solution at `27^(@)"C"`. Given R`=0.08"L""-atm"//"K""-mol"` |
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Answer» Correct Answer - 12.72 `"A"_("m")^("C")=("K"xx1000)/"C"=(0.006xx1000)/0.500=12" S cm"^(3)"mol"^(-1)` `"A"_("m")^("0")=200"scm"^(2)"mol"^(-1)` `alpha=("A"_("m")^("C"))/("A"_("m")^("0"))=0.06` For HA, `"n"=2` `"i"=1+("n"-1)alpha` `=1+(2-1)xx0.6` `"i"=1.06` `pi="i"xx"CRT"` `=1.06xx0.5xx0.082xx300` `pi=12.72"atm"` |
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