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The spin-only magnetic moment [in units of Bohr magneton, `(mu_(B)` of `Ni^(2+))` in aqueous solution would be (atomic number of `Ni=28)`A. `2.84`B. `4.9`C. 0D. `1.73` |
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Answer» Correct Answer - A `mu_(B) = sqrt(n(n+2))Ni^(+2) = 3d^(8)` Number of unpaired electrons = 2 |
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