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The temperature at which 10% aqeous solution `((W)/(V))` of glucose will exhibit the osmotic pressure of 16.4 atm, is : `(R = 0.082 "dm"^(2) "atm K"^(-1) "mol"^(-1))`A. `360^(@)C`B. 180 KC. 90 KD. 360 K |
Answer» Correct Answer - D `pi=nRT` `piV=(W)/(m)=RT` `16.4xx((100)/(1000))=(10)/(180)xx0.082xxT` `:. T=360K`] |
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