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The temperature of an iron piece is heated from `30^@ C "to" 90^@ C`. What is the change in its temperature on the fahrenheit scale and on the kelvin scale?A. `108^(@)`, 60KB. `100^(@)`F, 55 KC. `100^(@)`F, 65KD. `60^(@)`F, 108 K |
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Answer» a) `DeltaT_(c)=90^(@)-30^(@)`C=`60^(@)`C `DeltaT_(F) = 9/5DeltaT_(C) = 9/5(60^(@)) = 108^(@)`F `DeltaT = DeltaT_(c)=60K` |
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