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The tension in a piano wire is `10 N`. The tension ina piano wire to produce a node of double frequency isA. `20 N`B. `40 N`C. `10 N`D. ` 120 N` |
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Answer» Correct Answer - B For mass `m` per unit length of wire and tension `T`, the frequency of note emitted by the wire is `n=1/(2l)sqrt(T/m)` where `l` length of wire. Given `T_(1) = 10N, n_(1)=n` and `n_(2)=2n` `(n_(1))/(n_(2))=sqrt((T_(1))/(T_(2)))` `implies T_(2)= 10xx4= 40N` |
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