The theoretically computed equilibrium constant for the polymerisation of formaldehyde to glucose in aqueous solution : `6HCHO hArr C_6H_12O_6` is `1.0xx10^24` If 1 M-solution of glucose was taken, what should be the equilibrium concentration of formaldehyde ?A. `1.6 xx 10^(22) M`B. `1.6 xx 10^(-4) M`C. ` 6 sqrt(6xx10^(4)) xx 10^(3) M`D. None of these

The theoretically computed equilibrium constant for the polymerisation

1.	The theoretically computed equilibrium constant for the polymerisation of formaldehyde to glucose in aqueous solution : `6HCHO hArr C_6H_12O_6` is `1.0xx10^24` If 1 M-solution of glucose was taken, what should be the equilibrium concentration of formaldehyde ?A. `1.6 xx 10^(22) M`B. `1.6 xx 10^(-4) M`C. ` 6 sqrt(6xx10^(4)) xx 10^(3) M`D. None of these
Answer» Correct Answer - B A very high value of K indicates that amount of glucose dissociated into formaldehyde is negligible. Therefore , at equilibrium `[C_(6)H_(12)O_(6)]=1.0 mol L^(-1)` `K([C_(2)H_(12)O_(6)])/([HCHO]^(6))` `6xx10^(22)=(1)/([HCHO]^(6))` `[HCHO]^(6)=(1)/(6xx10^(22))` `implies [HCHO]=1.6 xx 10^(-4) M`

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