1.

The time constant for the given circuit under resonance condition will be?(a) \(\frac{1}{9}\) s(b) \(\frac{1}{4}\) s(c) 4 s(d) 9 sThis question was posed to me in an interview.Enquiry is from Advanced Problems on Resonance topic in section Resonance & Magnetically Coupled Circuit of Network Theory

Answer»

The correct choice is (c) 4 s

The best EXPLANATION: For finding the time constant, we neglect CURRENT source as an open circuit.

Hence, the circuit becomes:

So, from the above circuit, the Time constant = Req Ceq = 6 × \(\FRAC{2}{3}\) = 4 s.



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