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The total energy of the electron in the hydrogen atom in the ground state is `- 13.6 eV`. The `KE` of this electron is.A. `13.6 eV`B. zeroC. `- 13.6 eV`D. `6.8 eV` |
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Answer» Correct Answer - A (a) `because KE = (1)/(2) mv^2 = (Ze^2)/(2 r) , TE = - (Ze^2)/(2 r)`. |
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