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The transitionis `He^(o+)` ion that would have the same wavelength as the first Lyman line in hydtrogen spectrum isA. `2 rarr 1`B. `5 rarr 3`C. `4 rarr 2`D. `6 rarr 4` |
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Answer» Correct Answer - C `bar v _(He^(o+)) = (1)/(lambda) = R xx 2^(2) ((1)/(n_(1)^(2))- (1)/(n_(2)^(2)))` `= R ((4)/(n_(1)^(2)) - (4)/(n_(2)^(2)))`…..(i) `bar v _(theta_(2)^(o+)) = (1)/(lambda) = R xx ((1)/(1^(2))- (1)/(2^(2)))`….(ii) Compare equation (i) and (ii) we get `(1)/(1^(2)) = (4)/(n_(1)^(2)), n_(1)^(2)= 4 n_(1) = 2` `(4)/(n_(2)^(2)) = (1)/(2^(2)),n_(2)^(2)= 16 n_(2) = 4` `( h rarr 2)` |
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