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The uncertainty in momentum of an electron is `1 xx 10^-5 kg - m//s`. The uncertainty in its position will be `(h = 6.62 xx 10^-34 kg = m^2//s)`.A. `1.05xx10^(-28)` mB. `1.05xx10^(-26)` mC. `5.27xx10^(-30)` mD. `5.25xx10^(-28)`m

Answer» Correct Answer - C
According to `Deltax xx Deltap=h/(4pi)`
`Deltax=h/(Deltapxx4pi) =(6.62xx10^(-34))/(1xx10^(-5)xx4xx3.14)=5.27xx10^(-30) m`


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