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The uncertainty in momentum of an electron is `1 xx 10^-5 kg - m//s`. The uncertainty in its position will be `(h = 6.62 xx 10^-34 kg = m^2//s)`.A. `1.05 xx 10^-28 m`B. `1.05 xx 10^-26 m`C. `5.27 xx 10^-30 m`D. `5.25 xx 10^-28 m` |
Answer» Correct Answer - C ( c) According to `Delta x xx Delta p = (h)/(4 pi)` `Delta x = (h)/( Delta p xx 4 pi) = (6.62 xx 10^-34)/(1 xx 10^-5 xx 4 xx3.14)` =`5.27 xx 10^-32 m`. |
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