1.

The uncertainty in the momentum of a particle is `6.0 xx 10^(-2) kg m s^(-1)` .Calculate the uncertainty in the position

Answer» Uncertainty in momentum
`Delta p = 6 xx 10^(-2) kg m s^(-1)`
According to Heisenbery uncertainty principle
` Delta x xx Delta p = (h)/( 4pi)`
`Delta x = (h)/(Delta p xx 4pi)=(6.6 xx 10^(-34) kg m^(2)s^(-2))/(6 xx 10^(-2) kg m s^(-1) xx 4 xx3.14)`
`= 8.76 xx 10^(-34) m `
The uncertainty in its position is `8.76 xx 10^(-34) m`


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