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The unit of thermal conductivity is :A. ` Js^(-1) K`B. `Js^(-1) m^(2)k`C. `Jm^(-1)K`D. `Js^(-1) m^(-1) K^(-1)`

Answer» Correct Answer - D
`Q= (KA(theta_(1)-theta_(2)t)/l) `
`therefore` `K= (Q xx l)/(A(theta_(1) - theta_(2))t`
Unit of K = (Jm)/(m^(2)K-s)` = `J/(s-mK)`


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