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The value of `16^("log"4^(3))`, isA. 8B. 3C. 4D. 9 |
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Answer» Correct Answer - D We have, `16^("log"4^(3)) = 4^(2"log" 4 )""^(3) = 4^("log"4)""^(3^(2)) = 3^(2) = 9` |
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