1.

The value of `3(sin^4t+cos^4t-1)/(sin^6t+cos^6t-1)`is equal to __________

Answer» Correct Answer - 2
`sin^4t+cos^4t-1=(sin^2t=cos^2t)^2-2sin^2tcos^2t-1`
`=-2sin^2tcos^2t`
`sin^6t+cos^6t-1=(sin^2t+cos^2t)^3-3sin^2tcos^2t-1`
`=-3sin^2tcos^2t`
Hence, `3(sin^4t+cos^4t-1)/(sin^6t+cos^6t-1)`=2`


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