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The value of `3(sin^4t+cos^4t-1)/(sin^6t+cos^6t-1)`is equal to __________ |
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Answer» Correct Answer - 2 `sin^4t+cos^4t-1=(sin^2t=cos^2t)^2-2sin^2tcos^2t-1` `=-2sin^2tcos^2t` `sin^6t+cos^6t-1=(sin^2t+cos^2t)^3-3sin^2tcos^2t-1` `=-3sin^2tcos^2t` Hence, `3(sin^4t+cos^4t-1)/(sin^6t+cos^6t-1)`=2` |
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