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The value of `|alpha|` for which the system of equation `alphax+y+z=alpha-1` `x+alphay+z=alpha-1` `x+y+alphaz=alpha-1` has no solution , is `"____"`A. either -2 or 1B. -2C. 1D. not-2 |
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Answer» Correct Answer - B for no solution or infinitely many solutions `|{:(alpha ,,-1,,-1),(1,,-alpha,,-1),(1,,-1,,-alpha):}|=0` `" or " alpha(alpha^(2) -1)-1(alpha-1)+(1-alpha)=0` `" or " alpha(alpha^(2)-1) -2alpha +2=0` `" or " alpha(alpha -1) (alpha+1) -2(alpha -1)=0` `" or " (alpha-1)(alpha^(2) +alpha -2) =0` `" or " (alpha -1) (alpha+2)(alpha -1) =0` `" or " (alpha-1)^(2)(alpha+2)=0` `" or " alpha=1 ,1,-2` But for `alpha =1` there are infinite solution. when `alpha=-2` we have `-2x -y-z=-3` `x+2y -z=-3` `x-y +2z=-3` Adding we get 0=-9 which is not true . Hence there is no solution. |
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