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The value of `|alpha|` for which the system of equation `alphax+y+z=alpha-1` `x+alphay+z=alpha-1` `x+y+alphaz=alpha-1` has no solution , is `"____"` |
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Answer» Correct Answer - 2 System of equation `alpha x +y+ z=alpha-1` `x+alpha y+z = alpha-1 ` `x+y +alpha z =alpha -1` Since system has no solution Therefore (1) `Delta =0` and (2) `alpha -1 ne 0` `|{:(alpha,,1,,1),(1,,alpha,,1),(1,,1,,alpha):}|= 0, alpha ne 1` `R_(1) to R_(1) -R_(3),R_(2) to R_(2)-R_(3)` ` |{:(alpha-1,,0,,1-alpha),(0,,alpha-1,,1-alpha),(1,,1,,alpha):}|=0` `" or " (alpha-1 )[alpha(alpha-1)-(1-alpha)]+(-alpha)[-(alpha-1)]=0` `" or " (alpha-1 )[alpha(alpha-1)+(alpha-1)]+(alpha-1)^(2)=0` `" or " (alpha-1)^(2)[(alpha+1)+1]=0` `" or " alpha=1 ,1, -2 " or " alpha =1,-2` Sicne system has no solution `alpha ne 1` `:. alpha=-2` |
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