InterviewSolution
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InterviewSolution
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The value of `alpha`, which satisfy `int_(pi/2) ^(alpha) sin x dx = sin2alpha (alpha in [0,2pi]` are equalA. `pi/2`B. `(3pi)/2`C. `(7pi)/6`D. All of these |
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Answer» Correct Answer - D ` int_(pi//2)^(alpha) sin x dx = [ -cos x ] _(pi//2)^(alpha) = - cos alpha = sin 2 alpha ` [ Given] ` :. - cos alpha = 2 sin alpha cos alpha ` ` rArr cos alpha (2 sin alpha +1)=0` ` rArr cos alpha = 0 and sin alpha = -1/2 ` Since , `alpha (0,2pi)` Hence , ` alpha = pi/2 , (3pi)/2, (7pi)/6` |
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