1.

The value of `(bc)^log(b/c)*(ca)^log(c/a)*(ab)^log(a/b)` is

Answer» Correct Answer - C
We have,
`"log"{(ab)^("log"((a)/(b))) xx (bc)^("log"((b)/(c))) xx (ca)^("log"((c)/(a)))}`
`="log"((a)/(b))"log"(ab) + "log"((b)/(c)) "log" (bc) + "log"((c)/(a))"log"(ca)`
` =("log"a- "log"b)("log"a+ "log"b) + ("log"b-"log"c)("log"b + "log"c) + ("log"c-"log"a)("log"c + "log"a)`
= 0
`therefore (ab)^("log"((a)/(b))) xx (bc)^("log"((b)/(c))) xx (ca)^("log"((c)/(a))) = 1`


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