The value of equilibrium constant of the reaction, HI `hArr(1)/(2)H_(2) + (1)/(2)I_(2)` is `8` . The equilibrium constant of the reaction `H_(2)(g) + I_(2)(g)hArr2HI(g)` will beA. `1./16`B. `1//64`C. 16D. `1//8`

The value of equilibrium constant of the reaction, HI `hArr(1)/(2)H_(2

1.	The value of equilibrium constant of the reaction, HI `hArr(1)/(2)H_(2) + (1)/(2)I_(2)` is `8` . The equilibrium constant of the reaction `H_(2)(g) + I_(2)(g)hArr2HI(g)` will beA. `1./16`B. `1//64`C. 16D. `1//8`
Answer» Correct Answer - B For `HI(g) hArr (1)/(2)H_(2)(g)+(1)/(2) I_(2)(g) ,K=8` For `(1)/(2)H_(2)(g)+(1)/(2)I_(2)(g)hArr HI(g), K=(1)/(8)` For `H_(2)(g)+I_(2)(g) hArr 2HI(g)` `K=((1)/(8))^(2)=(1)/(64)`

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The value of equilibrium constant of the reaction, HI `hArr(1)/(2)H_(2) + (1)/(2)I_(2)` is `8` . The equilibrium constant of the reaction `H_(2)(g) + I_(2)(g)hArr2HI(g)` will beA. `1./16`B. `1//64`C. 16D. `1//8`

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