1.

The value of `int_(0)^(pi) x sin^(3) x dx ` isA. `(4pi)/3`B. `(2pi)/3`C. 0D. None of these

Answer» Correct Answer - B
Let `l = int_(0)^(pi)x sin^(3)x dx` ….(i)
Also, `l = int_(0)^(pi)(pi-x)sin^(3) x dx` …(ii)
On adding Eqs. (i) and (ii), we get
`2l=pi int_(0)^(pi)sin^(3)x dx`
`= (pi)/(4)int_(0)^(pi)(3 sin x - sin 3x)dx`
`= (pi)/(4)[-3 cos x + (cos 3x)/(3)]_(0)^(pi)=(4pi)/(3)`
Hence, `l = (2pi)/(3)`


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