InterviewSolution
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InterviewSolution
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The value of `int_(-pi//2)^(pi//2) log""((2-sintheta)/(2+sintheta))d theta` is |
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Answer» Correct Answer - A Let `f(theta) log ((2-sin theta)/(2+sin theta))` , Now, ` f(-theta) = log ((2+sin theta)/(2-sin theta) ) = - log ((2-sin theta)/(2+sin theta)) = - f(theta)` ` = [ -(x^(3))/3 + x]_(0)^(1) + [ (x^(3))/3-x]_(1)^(2) ` ` = - 1/3 + 1 + 8/3 - 2 - 1/3 + 1 = 2 ` ` :. f(theta) ` is an odd function . ` int _(-pi//2)^(pi//2) log ((2-sin theta )/(2+sin theta)) d theta = 0` |
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