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The value of integral `int_(-1)^(1) (|x+2|)/(x+2)dx` isA. 1B. 2C. 0D. `-1` |
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Answer» Correct Answer - B Let ` l = int _(-1)^(1) (|x+2|)/(x+2) dx ` For `-1 le xle 1, |x+2| = 2 +x` ` :. l = int _(-1)^(1)(x+2)/(x+2) dx = int _(-1)^(1) 1 dx ` ` [ x] _(-1)^(1)= 1 - (-1)=2` |
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