InterviewSolution
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InterviewSolution
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The value of integral ` int _(1//pi)^(2//pi)(sin(1/x))/(x^(2))dx=`A. 2B. `-1`C. 0D. 1 |
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Answer» Correct Answer - D Put `t=(1)/(x) rArr dt = -(1)/(x^(2))dx` at `t=(pi)/(2)` and `pi` `therefore int_(1//pi)^(2//pi)(sin((1)/(x)))/(x^(2))dx=-int_(pi)^(pi//2)sin t dt = [cos t]_(pi)^(pi//2)` `=[cos. (pi)/(2)-cos (pi)]=1` |
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