1.

The value of `l = int _(-pi//2)^(pi//2) | sin x | dx ` is

Answer» Correct Answer - B
` int _(-pi/2)^(pi/2) |sin x| dx =n 2x = 2 int _(0)^(pi//2) sin x dx = -2 [ cos x] _(0)^(pi/2)`
` = - 2(cos.pi/2 - cos 0) = 2 `
` :. int _(0)^(2a) f(x) dx = int _(0)^(a) [ f(2a - x) + f(x)] dx`


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