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The value of N in terms of attenuation D is?(a) antilog(D)(b) antilog(D/10)(c) antilog(D/20)(d) antilog(D/40)The question was asked in semester exam.Question is taken from Series Equalizer in portion Filters and Attenuators of Network Theory

Answer»

Correct answer is (B) antilog(D/10)

The EXPLANATION is: The value of N in TERMS of ATTENUATION D is antilog(D/10). N = antilog(D/10) where D is attenuation in DECIBELS.



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